Diagonal Difference || HackerRank C Programming Solution

Given a square matrix, calculate the absolute difference between the sums of its diagonals.

For example, the square matrix  is shown below:

1 2 3
4 5 6
9 8 9  

The left-to-right diagonal = . The right to left diagonal = . Their absolute difference is .

Function description

Complete the  function in the editor below.

diagonalDifference takes the following parameter:

• int arr[n][m]: an array of integers

Return

• int: the absolute diagonal difference

Input Format

The first line contains a single integer, , the number of rows and columns in the square matrix .
Each of the next  lines describes a row, , and consists of  space-separated integers .

Constraints

Output Format

Return the absolute difference between the sums of the matrix's two diagonals as a single integer.

Sample Input

3
11     2       4
4         5       6
10     8      -12

Sample Output

15

Explanation

The primary diagonal is:

11
         5
                -12

Sum across the primary diagonal: 11 + 5 - 12 = 4

The secondary diagonal is:

               4
         5
10

Sum across the secondary diagonal: 4 + 5 + 10 = 19
Difference: |4 - 19| = 15

Note: |x| is the absolute value of x

Solution:

#include<stdio.h>

int main()

{

    int n;

    scanf("%d",&n);

    int i,j,a[n][n],k=0,s=0;

    for(i=0;i<n;i++)

    {

        for(j=0;j<n;j++)

        {

            scanf("%d",&a[i][j]);

        }

    }

    for(i=0;i<n;i++)

    {

        for(j=0;j<n;j++)

        {

            if(i==j)

            {

                k=k+a[i][j];

            }

            if((i+j)==(n-1))

            {

                s=s+a[i][j];

            }

        }

    }

    int m;

    m=k-s;

    if(m<0)

    printf("%d",(-1)*m);

    else if(m>=0)

    printf("%d",m);

}